To begin the archetypal method I laid the ruler on a flat surface, and then I swung the mass in a circle above the ruler horizontally, going around the edges of the ruler. This creates a diameter of 30 centimeters. Dividing the diameter by 2 gives me a radius of 15 centimeters; converted to meters equals .15m. After finding the radius, I apply the timer in order to record the time it takes for one whole revolution, which was approximately 1.25 seconds. Lastly, I used the protractor to legal profession the angle, ?, to the vertical, which should be 16°. These two variables leave be used to prepare for the second method.
The second method I used involved looking at the forces happening in the x and y directions and applying centripetal force formulas in order to find the radius. There were two forces acting upon the mass and string: tensity (T) and gravity (Fg).
Because the mass was being held at an angle, force of tensity is calculated by Tcos74 in the y-direction and Tsin16 in the x-direction. Starting with the x-direction, thither is force of tension, Tsin16, and because it is moving, Tsin16 will equal ma (Tsin16 = ma). Because we are laborious to find out the radius, I changed ma to mr?^2 (Tsin16 = mr?^2). Therefore, r = Tsin16/m?^2. In order to solve this equation, we must find some(prenominal) T and ?. To find T, we must look into the y-direction. Because the mass is not moving up or down, Tcos74 = Fg. Therefore, T = mg/cos74. Now to look at ?. ? = ??/t; therefore, ? = 2? rads/1.25s, which will turn out to be 5.026548246. Now that we have both T and ?, we can finally start solving...If you want to position a full essay, order it on our website: Orderessay
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